Analysis for M20 Grade of Concrete in detail
M20 = 1:1.5:3 (Ratio)
We know that
In concrete work we have to convert the wet concrete volume to dry concrete volume which can get with multiplying from 1.54 to 1.57 with the wet volume of concrete
Example : Dry volume of concrete = 1.54 to 1.57 times volume of wet concrete.
Assume that we will find the materials calculation for 1 cum of concrete work.
So for M20 Grade of Concrete we have ratio = 1+1.5+3
Sum of ratio = 1+1.5+3
So total volume of is 1 cum.
Now change it the 1 cum volume of concrete to dry volume.
so , wet volume of concrete x 1.53
Dry volume of concrete = 1 x 1.57 = 1.57 cu.m
Now find the volume of cement = Volume of cement = (1/5.5) x 1.57 = 0.285 m3
Volume of cement in kg = 0.285 x 1440 = 411 kg where 1440 kg / cu.m
Volume of Sand = Volume of sand Require = (1.5/5.5) x 1.57 = 0.471 m3
Volume of Crush = (3/5.5) x 1.57 = 0.856 m3
Some useful Information for the above calculation in detail
Volume of Cement = 0.285 cu.m Or Cement = 8.22 bag Because one bag of Cement is equal to 50 kg.
Volume of Sand = 0.471 cu.m
Volume of Crush =0.856 cu.m
we know that Concrete proportion for M20 is (1:1.5:3)
8 bag of Cement is required for 1cum of concrete work in M20.
4.4 bag of cement is required for 1cum of concrete work in M10.
volume of dry concrete =1.54 times volume of wet concrete.
The above calculation you can use for all Grade of Concrete but just you have to put the different Grade of concrete like M10 , M15 , M20 , M25 etc. just here with grade of concrete you can change the proportion and the method is just above which I have discuss .